--- Log opened Thu Feb 03 00:00:48 2022
04:33 < adiabat> you can count it as (total_hashes)/(targets) where total_hashes includes targets.  
04:33 < adiabat> another way to say that: (proof_hashes + target_hashes) / target_hashes
04:35 < adiabat> or take the reciprocal so it doesn't go to infinity, but instead to 0 and call it overhead instead of efficiency
04:35 < adiabat> that would be proof_hashes / target_hashes
04:36 < adiabat> then if you had 3 targets and 1 proof the overhead would be 0.33
04:36 < adiabat> and deleting 14 would have overhead of 0 since no proof is needed
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--- Log closed Fri Feb 04 00:00:49 2022