But this will require user to distinguish 12 words from error correcting words. Which is another hassle.

On Thu, Jul 7, 2022, at 10:52 AM, Pavol Rusnak wrote:
There is. Just encode the index of permutation used to scramble the otherwise sorted list. For 12 words you need to store 12! = ~32 bits so 3 words should be enough. 

Repetitions make this more difficult, though. 

On Thu 7. 7. 2022 at 19:41, Bram Cohen via bitcoin-dev <bitcoin-dev@lists.linuxfoundation.org> wrote:
On Thu, Jul 7, 2022 at 7:43 AM Anton Shevchenko via bitcoin-dev <bitcoin-dev@lists.linuxfoundation.org> wrote:
I made a python implementation for a different mnemonic encoding. The encoding requires user to remember words but not the order of those words.
The code is open (MIT license) at https://github.com/sancoder/noomnem

Thanks Anton. There's an interesting mathematical question of whether it's possible to make a code like this which always uses the BIP-39 words for the same key as part of its encoding, basically adding a few words as error correction in case the order is lost or confused. If the BIP-39 contains a duplicate you can add an extra word.
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Best Regards / S pozdravom,

Pavol "stick" Rusnak
Co-Founder, SatoshiLabs