Den 1 feb 2015 00:37 skrev "Natanael" <natanael.l@gmail.com>:

>
> To bruteforce 8 decimals, on average you need (10^8)/2 = 50 000 000
tries. log(50M)/log(2) = 25.6 bits of entropy.

Oops. Used the wrong number in the entropy calculation. Add one bit, the
division by 2 wasn't supposed to be used in the entropy calculation.
Doesn't change the equation much, though.