From: James MacWhyte <macwhyte@gmail•com>
To: Paul Sztorc <truthcoin@gmail•com>,
Bitcoin Protocol Discussion
<bitcoin-dev@lists•linuxfoundation.org>
Subject: Re: [bitcoin-dev] No Order Mnemonic
Date: Fri, 8 Jul 2022 16:08:54 +0200 [thread overview]
Message-ID: <CAH+Axy4X+uQG5Vw0Efiz6AtNyK=++h-jDeZL1ZxpVJus8BVKeA@mail.gmail.com> (raw)
In-Reply-To: <CA+XQW1iKVRmEnyP-CGM2Fo4qHi3SQHUfjEmKftDdju-uxHViJg@mail.gmail.com>
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> What do you do if the "first" word (of 12), happens to be the last word in
> the list alphabetically?
>
That couldn't happen. If one word is the very last from the wordlist, it
would end up at the end of your mnemonic once you rearrange your 12 words
alphabetically.
However!
(@vjudeu) Choosing 11 random words and then sorting them alphabetically
before assigning a checksum would reduce entropy considerably. If you think
about it, to bruteforce the entire keyspace one would only need to come up
with every possible combination of 11 words + 1 checksum. I'm not the best
at napkin math, but I think that leaves you with around 10 trillion
combinations, which would only take a couple months to exhaust with
hardware that can do 1 million guesses per second.
James
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next prev parent reply other threads:[~2022-07-08 14:09 UTC|newest]
Thread overview: 14+ messages / expand[flat|nested] mbox.gz Atom feed top
2022-07-07 14:33 Anton Shevchenko
2022-07-07 17:36 ` Bram Cohen
2022-07-07 17:52 ` Pavol Rusnak
2022-07-07 17:58 ` Anton Shevchenko
2022-07-08 1:47 ` Bram Cohen
2022-07-08 2:19 ` Eric Voskuil
2022-07-08 4:35 ` vjudeu
2022-07-08 9:12 ` Paul Sztorc
2022-07-08 14:08 ` James MacWhyte [this message]
2022-07-09 20:31 ` Zac Greenwood
2022-07-09 22:21 ` James MacWhyte
2022-07-09 23:46 ` Anton Shevchenko
2022-07-11 13:11 ` Erik Aronesty
2022-07-11 13:18 ` Erik Aronesty
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