Sorting a seed alphabetically reduces entropy by ~29 bits.

A 12-word seed has (12, 12) permutations or 479 million, which is ln(469m)
/ ln(2) ~= 29 bits of entropy. Sorting removes this entropy entirely,
reducing the seed entropy from 128 to 99 bits.

Zac


On Fri, 8 Jul 2022 at 16:09, James MacWhyte via bitcoin-dev <
bitcoin-dev@lists.linuxfoundation.org> wrote:

>
> What do you do if the "first" word (of 12), happens to be the last word in
>> the list alphabetically?
>>
>
> That couldn't happen. If one word is the very last from the wordlist, it
> would end up at the end of your mnemonic once you rearrange your 12 words
> alphabetically.
>
> However!
>
> (@vjudeu) Choosing 11 random words and then sorting them alphabetically
> before assigning a checksum would reduce entropy considerably. If you think
> about it, to bruteforce the entire keyspace one would only need to come up
> with every possible combination of 11 words + 1 checksum. I'm not the best
> at napkin math, but I think that leaves you with around 10 trillion
> combinations, which would only take a couple months to exhaust with
> hardware that can do 1 million guesses per second.
>
>
> James
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