Session Start: Sat Jun 23 09:18:23 2007 Session Ident: #Chemistry [09:18] * Now talking in #Chemistry [09:18] * beta.PilotAge.com sets mode: +nt [09:18] * Disconnected Session Close: Sat Jun 23 09:18:28 2007 Session Start: Sun Jun 24 10:53:04 2007 Session Ident: #Chemistry [10:53] * Now talking in #Chemistry [10:53] * beta.PilotAge.com sets mode: +nt [11:56] * Don has joined #Chemistry [11:56] Hi Bunny [11:56] * Don has quit IRC (Leaving) [18:01] * Baryon has joined #Chemistry [18:01] * DrSturm has joined #Chemistry [18:05] * ProfSturm has joined #Chemistry [18:06] * ProfSturm has quit IRC [18:06] * DrSturm has quit IRC (Leaving) [18:10] * DrSturm has joined #Chemistry [18:15] * Baryon has quit IRC [18:15] * carbon has joined #Chemistry [18:17] Hi Dr.Sturm, I had a quick question about forming alkenes..if the alkyl halide is attached to a tertiary carbon, for example, CH3C(CH3)(Br)CH2Ch2CH3, how many products would that form? [18:17] Two [18:18] how about if it was CH3CH2C(CH3)(Br)CH2Ch2CH3 [18:19] Three [18:19] okay, that answers my question [18:19] thank you very much [18:20] * carbon has quit IRC (Leaving) [18:30] * dp has joined #Chemistry [18:33] On the homework ch.9 # 3 b, e - gives two products, I don't remember why two products would be the result? [18:38] b you can not use Markovnikov so would get two products, e should be one answer 2-iodo-2-methylbutane [18:38] On e the carbocation rearranges [18:39] * gg has joined #Chemistry [18:39] Hi Dr.Sturm. Why is it that HI rather used with peroxides or not gives Markovnikov addition? (Reference Ch#9 Problem 1g.) [18:39] thanks [18:40] The only thing that gives Anti-Mark with peroxides is HBr [18:41] So HI and HI/Peroxides would give the same product [18:43] thanks [18:44] * mp has joined #Chemistry [18:45] With the problem 10a. I find that doing the trans-2-butene they use potassium permaganate and yet they have an anti-configuration? I though the HCO2OH gave the anti-config. not KMnO4? [18:46] What chapter? [18:49] dr. sturm is element effect and isotope effect on the test? [18:49] KMnO4 adds syn and HCO2OH adds anti [18:49] no. [18:50] * guest has joined #Chemistry [18:51] do we need to know dehalogenation of vicinal halides? [18:51] Yes. [18:53] for the E and Z nomenclature, should we simply be able to identify what would be E or Z, or do we need to know more about it than that? [18:53] You should be able to use the E,Z convention to name alkenes and be able to draw an alkene as either E or Z [18:53] ok [18:55] on the test the only mechanisms are E1,E2 &HX? [18:55] Yes. [18:56] what is the HX mechanism? [18:56] The mechanism for the addition of HX to an alkene [18:57] oh ok [18:57] You must know that mechanism as it involves carbocation formation, i.e. could be rearrangements [18:57] ok [18:57] so we should be comfortable drawing it [18:58] Yes. [18:59] * mp has quit IRC (Leaving) [19:06] is saytzeff orientation the ease of formation and stability of an alkene, and also the way to predict the major product? [19:06] Yes. [19:06] So the most stable alkene will be the major project [19:07] ok, so when it says that something follows a saytzeff orientation it simply means that it adheres to the stability rules and ease of formation that the saytzeff puts in place? [19:07] Yes. [19:07] ok thank you [19:14] For stereoselective and stereospecific the chart on the handouts pg. 6 pretty much sums up what we need to know? [19:14] and how to recognize the application? [19:15] Addition of X2 is anti, KMnO4 hydroxylation is syn and HCO2OH hydroxylation is anti [19:15] thanks [19:16] * guest has quit IRC (Leaving) [19:22] thanks, see you tomorrow [19:22] * dp has quit IRC (Leaving) [19:30] * DrSturm has quit IRC [19:31] * Disconnected Session Close: Sun Jun 24 19:31:01 2007